TS EAMCET 2018 - Telangana Engineering, Agricultural and Medical Common Entrance Test 2018 answer key is available Now. TS EAMCET 2018 exam was conducted from 2nd to 7th of May 2018 by JNTU, Hyderabad on behalf of TSCHE, Telangana. This test is conducted in all districts of Telanganan through online mode.
Jawaharlal Nehru Technological University (JNTU), Hyderabad will release TS EAMCET 2018 Answer Key in online after the successful completion of the entrance exam.JNTU, Hyderabad will conduct it on behalf of Telangana State Council of Higher Education (TSCHE). The respective question paper along with response of the student and Preliminary key will be mailed to the registered mail id specified by the candidate while submitting the online application form. This information would also be ascertainable from the official website.
TS EAMCET 2018 Key Objections:
The answer key of TS EAMCET 2018 will help candidates to check their answers given by TSCHE. This way, candidates will be able to know their scores in the TS EAMCET exam and hence calculate their chances of admission in the institute and the course. JNTU will first release the TS EAMCET 2018 preliminary answer key on May 9th, 2018 receiving the objections on Preliminary Key from candidates.
It is important that candidates object TS EAMCET answers key 2018 with valid proofs and within the certain time period, otherwise their objections will not be considered by the university. The final answer key of TS EAMCET 2018 will be released by the JNTUH after considering all the valid objections. In this article we are giving the full information about TS EAMCET 2018 Preliminary Key, Final Key, Important dates and How to Object the Key and important things to remember.
TS EAMCET 2018 Key:
Preliminary key is the key released by the JNTU, Hyderabad in Behalf of TSCHE immediately after conducting the TS EAMCET 2018 exam for the candidate's reference. Candidates can check their options answered in the exam by comparing the preliminary key. This TS EAMCET 2018 Key helps the students to evaluate their answers and also counter foil the answer key released by the TSCHE.
Those who have any objections in the TS EAMCET 2018 Preliminary key can appeal to the TSCHE for re-checking the TS EAMCET 2018 Key. The TSCHE has all rights to consider or not to consider the appeal. Based upon the appeals court and correctness of the mistakes raised in the appeal the TSCHE may consider and provide extra marks to the aspirants. Official date for TS EAMCET 2018 Preliminary Key releasing on 9th May for Engineering and 10th May for Agriculture.
Important dates of TS EAMCET 2018 Answer Key:
TS EAMCET 2018 entrance exam
May 02-07, 2018
Release of TS EAMCET preliminary answer key 2018
May 07, 2018
Last date for filing objections on preliminary answer key of TS EAMCET 2018
Now click on the title "TS EAMCET Answer Key 2018".
Choose the question paper booklet code that you wrote in the exam
Download the Booklet along with Answer Key
Check your answers
Evaluate your scores
EAMCET 2018 marks Normalization Process:
The main aim of the normalization is to justify the candidates who got a difficult paper compared to an easier paper. Hence, the task is to rationalize in a best possible sense and rank the candidates based on the global performance. Various national level examination bodies like JEE (Main), GATE etc. are currently adopting such normalization procedures. Correspondingly, EAMCET committee has deliberated extensively and decided to use the following normalization procedure.
Normalized Marks of the candidate =
GMS+ (Top Average Global - GMS) / (Top Average Session - SMS)
× (M arks obtained of the candidate - SMS)
SMS :( Average + Standard Deviation) of the session in which the candidate belongs to
GMS: (Average + Standard Deviation) of all the candidates across all sessions together
Top Average Session: Average marks of the top 0.1% of the candidates in the session in which the candidate belongs to
Top Average Global: Average marks of the top 0.1% of all the candidates across all sessions Together
Weight age for assigning merit ranks:
75% of EAMCET normalized marks and 25% of Intermediate Marks in group subjects to prepare the rank.
a. For Candidates having qualifying marks in TS EAMCET-2018, if after normalization, the marks(s) in any individual subject(s) become negative, then the normalized mark(s) in the respective subject(s) are treated as zero.
However, total marks in three subjects are considered as EAMCET marks.
b. For the candidates for whom there is no qualifying cut off in TS EAMCET - 2018, if the marks in all the three subjects after normalization goes below zero (negative), the total marks is treated as zero and the rank is assigned based on 25% of Intermediate marks weight age. If the tie persists, then TS EAMCET 2018 normalization marks (though negative) are considered for breaking the tie.
the candidates who have secured qualifying marks in TS EAMCET-2018 and candidates belonging to the category of Scheduled Caste and Schedule Tribe, for whom qualifying marks have not been prescribed, shall be assigned ranking in the order of merit on the basis of combined score obtained by giving 75% weight age to the marks secured in TS EAMCET-2018 and 25% weight age to the marks secured in the relevant group subjects namely Biology, Physics, Chemistry of the qualifying examination.
For the preparation of merit list, in case of more than one student securing the same combined score obtained as mentioned above, the tie shall be resolved to decide the relative ranking by successively considering the following
The total marks secured in TS EAMCET-2018
The marks secured in Biology in TS EAMCET-2018
The marks secured in Physics in TS EAMCET-2018
The percentage of aggregate marks secured in the qualifying examination
If the tie still persists the date of birth of the concerned candidates, the older being given preference over the younger.
The weight age of marks in the case of candidates belonging to the category of Persons of Indian Origin (PIO) / Overseas Citizen of India (OCI) Card Holders, will be decided by a committee constituted by the competent authority.