Admission in IIMs for the Fellow Programme in Management using GATE Score
Total number of candidates appearing in GATE….
Year
|
Number of candidates appearing
|
2014
|
889,156
|
2013
|
984,855
|
2012
|
686,614
|
2011
|
553,000
|
2010
|
414,000
|
2009
|
230,000
|
Normalized GATE Score (new procedure) Normalized GATE Score (new procedure)
Calculation of "normalized marks" for subjects held in multiple sessions (CE, CS, EC, EE and ME): Calculation of "normalized marks" for subjects held in multiple sessions (CE, CS, EC, EE Calculation of "normalized marks" for subjects held in multiple sessions (CE, CS, EC, EE

Graph showing the linear relationship between "actual marks" and "normalized multiple-session subject (CE, EE, ME, EE or CE) of GATE.
Mg t = average marks of top 0.1 % of the candidates in all sessions of that subject.
M g q = mean + standard deviation, of marks of all candidates in all sessions of that subject
Mti = average marks of top 0.1 % of candidates in the ith session of that subject
Miq = mean + standard deviation, of marks of candidates in the ith session of that subject
In 2014, examination for CE, CS, EC, EE and ME subjects is being held in multiple sessions. Hence, for these subjects, a suitable normalization is applied to take into account any variation in the difficulty levels of the question sets across different sessions.
The normalization is done based on the fundamental assumption that in all multi session GATE Papers, the distribution of abilities of candidates is the same across all the sessions"
According to the GATE COMMITTEE this assumption is justified since "the number of candidates appearing in multi in GATE 2014 is large and the procedure of allocation of session to candidates is random.
Further it is also ensured that for the same multi-session subject the number of candidates allotted in each session is of the same order of magnitude."
Based on the above, and considering various normalization methods, the committee arrived at the following formula for calculating the normalized marks, for CE, CS, EC, EE and ME subjects:
Normalized mark (Mij) of jth Candidate in ith session, is given by
Mij = {(Mgt - Mgq) / ( Mij - Miq )}[ Mti - Miq ] + Mgq
Where
Mij is the actual marks obtained by the jth candidate in the ith session,
Mgt is the average marks of the top 0.1% of the candidates in all sessions of that subject,
Mgq is the sum of mean and standard deviation of marks of all candidates in all sessions of that subject,
Mti is the average of marks of top 1.0% of candidates in the ith session of that subject,
Miq is the sum of mean and standard deviation of marks of candidates in the ith session of
that subject
After evaluation of the answers, normalized marks based on the above
formula will be calculated using the raw (actual) marks obtained by
candidate in the CE, CS, EC, EE or ME subject. The "score" will be
calculated using these normalized marks. For all other subjects (whose tests
are conducted in a single session), the actual marks obtained by the
candidates will be used in calculating the score
calculation of GATE Score for all subject (both single-session and multiple-session):
Graph showing the linear relationship between marks and score in GATE.
Mq = Qualifying marks for general category candidates.
Mt = Average marks of top 0.1 % or top 10 (whichever is higher) candidates.
Sq=350.
St=900.
Note: In case of multiple -session subject (EC,CS,ME,EE and CE),"marks" considered are the "normalized marks".
From GATE 2014 onward (and year 2014-15of the 2-year validity period of GATE 2013 score), a candidate`s GATE score is computed by the following new formula .[10]