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##### Question (a). Quadrilateral ABCD with AB = 5.5 cm, BC = 3.5 cm, CD = 4 cm, AD = 5 cm and ∠A = 45°.

Solution:
In Quadrilateral ABCD with AB = 5.5 cm, BC = 3.5 cm, CD = 4 cm, AD = 5 cm and ∠A = 45°.

##### Question (b). Quadrilateral BEST with BE = 2.9 cm, ES = 3.2 cm, ST = 2.7 cm, BT = 3.4 cm and ∠B=75°.

Solution:
BE = 2.9 cm, ES = 3.2 cm, ST = 2.7 cm, BT = 3.4 cm and ∠B=75°.

##### Question (c). Parallelogram PQRS with PQ = 4.5 cm, QR =3 cm and ∠PQR = 60°.

Solution:

In a parallelogram PQRS
PQ = 4.5 cm, QR = 3 cm, ZPQR = 60°.
=RS4.5cmzPS=3crn
[: Opposite sides of a I)aralielograrn are equal]

Construction Steps:

1. Draw a line segment ¡i with radius 4.5 cm.
2. With the centre Q draw a ray and an arc equal to 60° and 3 cm.
3. The intersecting point of these two keep as R’.
4. With the centres R, P draw arcs with 4.5 cm, 3 cm respectively. Keep ‘S’ as the intersecting point of these two arcs.
5. Join P, S and R, S.
6. ∴ The required parallelogram PQRS is formed.

Solution:

##### Question (e). Rectangle FLAT with FL =5 cm, LA= 3 cm.

Solution:

In a rectangle FLAT
FL=AT=5cm, LA = TF = 3cm, ∠F = ∠L = ∠A = ∠T = 90°

##### Question (f). Square LUDO with LU = 4.5 cm.

Solution:

In a square LUDO
LU = UD = DO = OL = 4.5 cm
∠L = ∠U = ∠D = ∠O = 90°

##### Question (a). Quadrilateral ABCD with AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm andAC= 7cm

Solution:
In Quadrilateral ABCD with AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm and AC = 7 cm.

1. With the centres A, B draw arcs equal to 7 cm and 5.5 cm respectively. The intersection of these two arcs keep as ‘C’.
2. Join A, C and B, C.
3. With centres C, A draw arcs equal to 4 cm, 6 cm respectively. These intersecting point is keep as ’D’.
Join D, C and A, D.
4. ∴ The required quadrilateral ABCD is formed.
##### Question (b). Quadrilateral PQRS with PQ = 3.5 cm, QR = 4 cm, RS = 5 cm, PS = 4.5 cm and QS= 6.5 cm

Solution:
PQ = 3.5 cm, QR = 4 cm, RS = 5 cm,
PS - 4.5 cm, QS = 6.5 cm

1. With the centres P, Q draw arcs equal to 4.5 cm and 6.5 cm respectively.
2. These two arcs meet at point ‘S’.
3. With the centres S, Q draw arcs with radius 5 cm, 4 cm respectively. These two arcs intersected at point ‘R’.
4. Join P, S; Q, S; S, R and Q, R.
5. ∴ The required quadrilateral PQRS is formed.
##### Question (c). Parallelogram ABCD with AB = 6cm, CD = 4.5 cm and BD = 7.5 cm

Solution:
In a parallelogram ABCD; AB = 6 cm, BC = 4.5 cm, BD = 7.5 cm
AB = CD (;cm
BC = AD = 4.5 cm
BD = 7.5 cm

1. With the centres A, B draw arcs with radius 4.5 cm, 7.5 cm respectively. These two arcs meet at point ‘D’.
2. With the centres D, B draw arcs with radius 6 cm, 4.5 cm respectively. These two arcs meet at point ‘C’.
3. Join A, D and B, C and D, C and B, D.
4. ∴ The required parallelogram ABCD is formed.
##### Question (d). Rhombus NICE with NI = 4 cm and IE = 5.6 cm

Solution:
In a rhombus NI = IC = CE = NE = 4 cm, IE = 5.6 cm

1. With the centres N, I draw two arcs with radius 4 cm, 5.6 cm respectively. These two arcs meet at point E’.
2. With the centres E, I draw arcs with radius 4 cm. These two arcs meet at point ‘C’.
3. Join N, E and I, E. Also join E, C and I, C.
4. .’. The required rhombus NICE is formed.
##### Question a). Quadrilateral GOLD: OL = 7.5 cm, GL = 6 cm, LD = 5 cm, DG = 5.5 cm and OD = 10 cm. (Ex 3.3, Page No. 72)

Solution:
In a quadrilateral GOLD, Rough Diagram
OL = 7.5 cm, GL = 6 cm
LD = 5 cm, DG = 5.5 cm, OD = 10 cm

1. With the centres O, L draw arcs with radius 10 cm and 5 cm respectively. These two arcs meet at point ‘D’.
2. With the centres L, D draw arcs equal to 6 cm and 5.5 cm respectively. These two arcs meet at point ‘G’.
3. Join O, G and L, G. Also join O, D and L, D and G, D.
4. ∴ The required quadrilateral GOLD is formed.
##### Question b). Quadrilateral PQRS: PQ = 4.2 cm, QR = 3 cm, PS = 2.8 cm, PR = 4.5 cm and QS = 5 cm.

Solution:

PQ = 4.2 cm PS = 2.8 cm
QR = 3 cm PR = 4.5 cm
QS = 5 cm

1. With the centres P, Q draw arcs equal to the radius 4.5 cm, 3 cm respectively. These two arcs meet at point R’. Join P, R and Q, R.
2. With the centres Q, P draw arcs equal to the radii 5 cm and 2.8 cm respectively. These two arcs meet at point ‘S’.
3. Join P, S and Q, S and S, R.
4. ∴ The required PQRS quadrilateral is formed.