NCERT Solutions 10th Maths Chapter 8 Introduction to Trigonometry Exercise 8.1

NCERT Solutions For Class 10 Maths Chapter 8 Exercise 8.1 we will restart our exploration of the world of Introduction to Trigonometry. Thus, we are providing you Chapter 8 Introduction to Trigonometry NCERT Class 10 Maths Solutions that will help in achieving more marks. You don't have to wander and waste your precious time in finding best CBSE NCERT Solutions.

Exercise 8.1
1. In Δ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine :
(i) sin A, cos A
(ii) sin C, cos C
Solution:
In Δ ABC,∠B = 90º
By Applying Pythagoras theorem , we get

AC2 = AB2 + BC2 = (24)2 + 72 = (576+49) cm2 = 625 cm2
⇒ AC = 25
(i) sin A = BC/AC = 7/25 cos A = AB/AC = 24/25
(ii) sin C = AB/AC = 24/25
cos C = BC/AC = 7/25

2.Find the distance between the points (0, 0) and (36, 15).
Solution:
Let the given points be P(0, 0) and Q(36, 15).
Then x1 = 0, y1 = 0, x2 = 36 and y2 = 15

3.In ∆ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine:
(i) sin A, cos A
(ii) sin C, cos C
Solution:

4.If sin A = \frac { 3 }{ 4 } , calculate cos A and tan A.
Solution:

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