NCERT Solutions 10th Maths Chapter 5 Arithmetic Progressions Exercise 5.4

NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.4 we will restart our exploration of the world of Arithmetic Progressions. Thus, we are providing you Chapter 5 Arithmetic Progressions NCERT Class 10 Maths Solutions that will help in achieving more marks. You don't have to wander and waste your precious time in finding best CBSE NCERT Solutions.

Exercise 5.4
1. Which term of the AP : 121, 117, 113, . . ., is its first negative term?
[Hint : Find n for an < 0]
Answer
We have the A.P. having a = 121 and d = 117 - 121 = - 4
? an = a + (n - 1) d
= 121 + (n - 1) × (- 4)
= 121 - 4n + 4
= 125 - 4n
For the first negative term, we have
an < 0
? (125 - 4n) < 0
? 125 < 4n
? 125/4 ? n > 31 1/4
Thus, the first negative term is 32nd term.
2. The houses of a row are numbered consecutively from 1 to 49. Show that there is a value of x such that the sum of the numbers of the houses preceding the house numbered x is equal to the sum of the numbers of the houses following it. Find this value of x.
[Hint : Sx-1 = S49 – Sx]
Answer

3. A ladder has rungs 25 cm apart. (see Fig. 5.7). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are 21/2 m apart, what is the length of the wood required for the rungs?
[Hint : Number of rungs = 250/25 + 1]

Answer

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