Solutions

Human Eye and Colourful World

NCERT Questions

Question1.
What is meant by power of accommodation of the eye?

Answer:The images of objects at different distances from the eye are brought to focus on retina by changing the focal length of the eye lens. This is known as power of accommodation of the eye

Question2.
What is the near point and the far point of a normal human eye?

Answer:Near point is 25 cm and far point is infinity

Question3.
A student has difficulty reading the blackboard while sitting in the last row. What could be the defect the child is suffering from? How can it be corrected?

Answer:The child is suffering from myopia. It can be corrected by using spectacles with concave lenses of suitable focal length

Question4.
A person with a myopic eye cannot see objects beyond 1.2 m distinctly. What should be the type of the corrective lens used to restore proper vision?

Answer:A concave lens of focal length 1.2 m should be used to restore proper Vision

Chapter End Questions

Question1.
human eye can, focus objects at different distances by adjusting the focal length of the eyelens. This is due to?
  • presbyopia
  • accommodation
  • near-sightedness
  • far-sightedness

Answer:

  • accommodation
Question2.
The human eye forms the image of an object at its?
  • cornea
  • iris
  • pupil
  • retina

Answer:

  • retina
Question3.
The least distance of distinct vision for a young adult with normal vision is about ?
  • 25 m
  • 2.5 cm
  • 25 cm
  • 2.5 m

Answer:

  • 25 cm
Question4.
The change in focal length of an eye lens is caused by the action of the?
  • pupil
  • retina
  • ciliary muscles
  • iris

Answer:

  • ciliary muscles
Question5.
A person needs a lens of power -5.5 D for correcting his distant vision. For correcting his near vision, he needs a lens of power +1.5 D. What is the focal length of the lens required for correcting?
  • (a) distant vision?
  • (b) near vision?

Answer:

Question6.
The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

Answer:Given: Distance of far point = 80 cm, P= ?
For viewing far-off objects, the focal length of corrective lens

Question7.
Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm?

Answer:The required diagram is shown below

Question8.
Why is a normal eye not able to see clearly the objects placed closer than 25 cm?

Answer:A normal eye is not able to see clearly the objects placed closer than 25 cm because the focal length of eye lens cannot be decreased below a certain minimum limit

Question9.
What happens to the image distance in the eye when we increase the distance of an object from the eye?

Answer:In order to focus the eye on objects situated at varying distances, the focal length of the eye lens is changed by the action of ciliary muscles

Question10.
Why do stars twinkle?

Answer:The rays of starlight pass through many layers of atmosphere. These layers have different densities and hence, different refractive indices. So the directions of rays reaching the eye keep changing causing the image of the star to shift in random directions or eyen disappear for an instant. Thus, the brightness of the star seems to change

Question11.
Explain why the planets do not twinkle?

Answer:Planets are comparatively much closer to the earth and are thus seen as extended sources of light. Being of larger size, planets can be taken as a collection of a number of point-sized sources of light which nullify the twinkling effect of each other

Question12.
Why does the sun appear reddish early in the morning?

Answer:At the time of shnrise, the rays of the sun have to travel a larger atmospheric distance. As the wavelength of red colour is the largest of all the colours of sunlight, most of the blue colour and other colours are scattered away. Only red. colour which is least scattered, enters into our eyes. Hence, the sun appears reddish at the time of sunrise

Question13.
Why does the sky appear dark instead of blue to an astronaut?

Answer:This is because there is no scattering of light due to the absence of atmosphere in the free space.

We hope the NCERT Solutions for Class 10 Science Chapter 11 Human Eye and Colourful World help you. If you have any query regarding NCERT Solutions for Class 10 Science Chapter 11 Human Eye and Colourful World, drop a comment below and we will get back to you at the earliest

Important Question

The Human Eye and Colourful World Chapter 11 Important Question & Answers

Question1.
What is meant by power of accommodation of the eye?
Year of Question :(2012)

Answer: The ability of the lens of the eye to adjust its focal length to clearly focus rays coming from distant as well from a near objects on the retina, is known as the power of accommodation of the eye

Question2.
A person with a myopic eye cannot see objects beyond 1.2 m distinctly. What should be the type of corrective lens used to restore proper vision?
Year of Question :(2012)

Answer: An individual with a myopic eye should use a concave lens of focal length 1.2 m so that he or she can restore proper vision

Question3.
What is the far point and near point of the human eye with normal vision?
Year of Question :(2013)

Answer: The minimum distance of the object from the eye, which can be seen distinctly without strain is called the near point of the eye. For a normal persons eye, this distance is 25 cm. The far point of the eye is the maximum distance to which the eye can see objects clearly. The far point of a normal persons eye is infinity

Question4.
A student has difficulty reading the blackboard while sitting in the last row. What could be the defect the child is suffering from? How can it be corrected?
Year of Question :(2012)

Answer: The student is suffering from short-sightedness or myopia. Myopia can be corrected by the use of concave or diverging lens of an appropriate power

Exercise

Question1.
The human eye can focus objects at different distances by adjusting the focal length of the eye lens. This is due to?
Year of Question :(2012)
  • (a) presbyopia
  • (b) accommodation
  • (c) near-sightedness
  • (d) far-sightedness

Answer:

  • (b) accommodation Due to accommodation the human eye can focus objects at different distances by adjusting the focal length of the eye lens
Question2.
The human eye forms an image of an object at its?
Year of Question :(2016)
  • (a) cornea
  • (b) iris
  • (c) pupil
  • (d) retina

Answer :

  • (d) retina The retina is the layer of nerve cells lining the back wall inside the eye. This layer senses light and sends signals to the brain so you can see
Question3.
The least distance of distinct vision for a young adult with normal vision is about?
Year of Question :(2012)
  • (a) 25 m
  • (b) 2.5 cm
  • (c) 25 cm
  • (d) 2.5 m

Answer:

  • (c) 25 cm
  • 25 cm is the least distance of distinct vision for a young adult with normal vision.
Question4.
The change in focal length of an eye lens is caused by the action of the?
Year of Question :(2015)
  • (a) pupil
  • (b) retina
  • (c) ciliary muscles
  • (d) iris

Answer:

  • (c) ciliary muscles The action of the ciliary muscles changes the focal length of an eye lens
Question5.
A person needs a lens of power -5.5 dioptres for correcting his distant vision. For correcting his near vision he needs a lens of power +1.5 dioptre. What is the focal length of the lens required for correcting (i) distant vision, and (ii) near vision?
Year of Question :(2012)

Answer: The power (P) of a lens of focal length f is given by the relation Power (P) = 1/f

  • (i) Power of the lens (used for correcting distant vision) = - 5.5 D Focal length of the lens (f) = 1/P f = 1/-5.5 f = -0.181 m The focal length of the lens (for correcting distant vision) is - 0.181 m
  • (ii) Power of the lens (used for correcting near vision) = +1.5 D Focal length of the required lens (f) = 1/P f = 1/1.5 = +0.667 m The focal length of the lens (for correcting near vision) is 0.667 m
Question6.
The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?
Year of Question :(2012)

Answer: The individual is suffering from myopia. In this defect, the image is formed in front of the retina. Therefore, a concave lens is used to correct this defect of vision. Object distance (u) = infinity = ? Image distance (v) = - 80 cm Focal length = f According to the lens formula, A concave lens of power - 1.25 D is required by the individual to correct his defect

Question7.
Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm?
Year of Question :(2014)

Answer: An individual suffering from hypermetropia can see distinct objects clearly but he or she will face difficulty in clearly seeing objects nearby. This happens because the eye lens focuses the incoming divergent rays beyond the retina. This is corrected by using a convex lens. A convex lens of a suitable power converges the incoming light in such a way that the image is formed on the retina, as shown in the following figure The convex lens creates a virtual image of a nearby object (N in the above figure) at the near point of vision (N) of the individual suffering from hypermetropia. The given individual will be able to clearly see the object kept at 25 cm (near point of the normal eye), if the image of the object is formed at his near point, which is given as 1 m. Object distance, u= - 25 cm Image distance, v= - 1 m = - 100 m Focal length, f Using the lens formula, A convex lens of power +3.0 D is required to correct the defect

Question8.
Why is a normal eye not able to see clearly the objects placed closer than 25 cm?

Answer: A normal eye is not able to see the objects placed closer than 25 cm clearly because the ciliary muscles of the eyes are unable to contract beyond a certain limit

Question9.
What happens to the image distance in the eye when we increase the distance of an object from the eye?
Year of Question :(2012)

Answer: The image is formed on the retina even on increasing the distance of an object from the eye. The eye lens becomes thinner and its focal length increases as the object is moved away from the eye

Question10.
Why do stars twinkle?
Year of Question :(2015)

Answer: The twinkling of a star is due to atmospheric refraction of starlight. The starlight, on entering the earths atmosphere, undergoes refraction continuously before it reaches the earth. The atmospheric refraction occurs in a medium of gradually changing refractive index

Question11.
Explain why the planets do not twinkle?
Year of Question :(2012)

Answer: Unlike stars, planets dont twinkle. Stars are so distant that they appear as pinpoints of light in the night sky, even when viewed through a telescope. Since all the light is coming from a single point, its path is highly susceptible to atmospheric interference (i.e. their light is easily diffracted)

Question12.
Why does the Sun appear reddish early in the morning?
Year of Question :(2012)

Answer: White light coming from the sun has to travel more distance in the atmosphere before reaching the observer. During this, the scattering of all coloured lights except the light corresponding to red colour takes place and so, only the red coloured light reaches the observer. Therefore, the sun appears reddish at sunrise and sunset

Question13.
Why does the sky appear dark instead of blue to an astronaut?
Year of Question :(2013)

Answer: The sky appears dark instead of blue to an astronaut, as scattering of light does not take place outside the earths atmosphere

Important Questions and Answers Chapter 11: The Human Eye and The Colourful World

Question 1.
What is the structure and function of the human eye?

Answer:
"Cornea": The front part of the eye through which light enters.
"Lens": A flexible, transparent structure that focuses light on the "retina".
"Retina": The light-sensitive layer at the back of the eye.
"Pupil": A small opening that controls how much light enters the eye.
"Iris": The colored part of the eye, which adjusts the size of the pupil.
"Optic Nerve": Sends visual information from the retina to the brain.

Question 2.
What is meant by "Power of Accommodation" of the eye?

Answer:
The "Power of Accommodation" refers to the ability of the eye to focus on both near and far objects by changing the shape of the lens.
Ciliary muscles adjust the curvature of the lens to help focus light on the retina.
For distant objects, the lens becomes thinner, and for near objects, the lens becomes thicker.

Question 3.
What are the defects of vision? How are they corrected?

Answer:
Myopia (Near-Sightedness):
A person can see near objects clearly but cannot see distant objects.
Cause: The image forms in front of the retina.
Correction: By using "concave lenses" to move the image back to the retina.
Hypermetropia (Far-Sightedness):
A person can see distant objects clearly but not near ones.
Cause: The image forms behind the retina.
Correction: By using "convex lenses" to focus light correctly on the retina.
Presbyopia:
A defect that occurs with aging, where both near and distant vision become difficult.
Cause: Weakening of ciliary muscles.
Correction: By using bifocal lenses, which have both concave and convex lenses.

Question 4.
What is "dispersion" of light? Explain with an example.

Answer:
"Dispersion" is the splitting of white light into its seven component colors: Violet, Indigo, Blue, Green, Yellow, Orange, and Red (VIBGYOR).
Example: A "prism" splits white light into a spectrum of colors when light passes through it. The "red" light bends the least, while the "violet" light bends the most.

Question 5.
How does a rainbow form?

Answer:
A rainbow is formed by the "dispersion" of sunlight through "water droplets" in the atmosphere.
The sunlight is refracted, reflected, and then dispersed by the water droplets.
The colors are seen in the order of VIBGYOR from top to bottom.

Question 6.
Why do stars twinkle?

Answer:
Stars twinkle due to "atmospheric refraction".
The light from a star passes through layers of air with different densities, which causes the light to bend slightly.
As the atmosphere changes, the position of the star’s light fluctuates, making the star appear to twinkle.

Question 7.
Why don’t planets twinkle like stars?

Answer:
Planets are much closer to the Earth and appear as extended sources of light.
Light from different parts of the planet reaches the observer’s eye, so the slight bending averages out, preventing twinkling.

Question 8.
Why does the Sun appear red at sunrise and sunset?

Answer:
At sunrise and sunset, sunlight travels a longer distance through the atmosphere.
"Scattering" of shorter wavelengths (like blue) is greater, and only the longer wavelengths, such as red, reach our eyes.
This makes the Sun appear red.

Question 9.
What is the "Tyndall Effect"?

Answer:
The "Tyndall Effect" is the scattering of light by colloidal particles in the atmosphere.
Example: When sunlight passes through a dense forest, the tiny water droplets scatter the light, making the path of the light beam visible.

Question 10.
Why is the sky blue?

Answer:
The sky appears blue due to the "scattering" of light by the atmosphere.
Shorter wavelengths like blue scatter more than longer wavelengths like red.
This scattered blue light enters our eyes, making the sky appear blue.

Question 11.
What is the least distance of distinct vision?

Answer:
The "least distance of distinct vision" is the minimum distance at which an object can be seen clearly without straining the eyes.
For a person with normal vision, this distance is about 25 cm.

Question 12.
Explain atmospheric refraction and its effect on sunrise and sunset.

Answer:
Atmospheric refraction is the bending of light as it passes through layers of the atmosphere with varying densities.
It causes the Sun to appear 2 minutes earlier at sunrise and 2 minutes later at sunset than its actual position.

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