About UPSC:
The Union Public Service Commission, commonly abbreviated as UPSC, is India`s premier central recruiting agency. It is responsible for appointments to and examinations for All India services and group A & group B of Central services. While Department of Personnel and Training is the central personnel agency in India.
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if (ad.getBoundingClientRect().width) {
adWidth = ad.getBoundingClientRect().width; // for modern browsers
} else {
adWidth = ad.offsetWidth; // for old IE
}
/* Replace ca-pub-XXX with your AdSense Publisher ID */
google_ad_client = "ca-pub-2551325655874098";
/* Replace 1234567890 with the AdSense Ad Slot ID */
google_ad_slot = "6713161600";
/* Do not change anything after this line */
if ( adWidth >= 728 )
google_ad_size = ["728", "90"]; /* Leaderboard 728x90 */
else if ( adWidth >= 468 )
google_ad_size = ["468", "60"]; /* Banner (468 x 60) */
else if ( adWidth >= 336 )
google_ad_size = ["336", "600"]; /* Large Rectangle (336 x 280) */
else if ( adWidth >= 300 )
google_ad_size = ["300", "600"]; /* Medium Rectangle (300 x 250) */
else if ( adWidth >= 250 )
google_ad_size = ["250", "250"]; /* Square (250 x 250) */
else if ( adWidth >= 200 )
google_ad_size = ["200", "200"]; /* Small Square (200 x 200) */
else if ( adWidth >= 180 )
google_ad_size = ["180", "150"]; /* Small Rectangle (180 x 150) */
else
google_ad_size = ["125", "250"]; /* Button (125 x 125) */
document.write (
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);
(adsbygoogle = window.adsbygoogle || []).push({});
Vacancy Details:
Post Name: Assistant Engineer
No of Posts: 03
Age Limit :
Minimum : 30 Years
Maximum : 38 Years
Pay scale : 35000-50000/- Per Month
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/* Calculate the width of available ad space */
ad = document.getElementById(`google-ads-1`);
if (ad.getBoundingClientRect().width) {
adWidth = ad.getBoundingClientRect().width; // for modern browsers
} else {
adWidth = ad.offsetWidth; // for old IE
}
/* Replace ca-pub-XXX with your AdSense Publisher ID */
google_ad_client = "ca-pub-2551325655874098";
/* Replace 1234567890 with the AdSense Ad Slot ID */
google_ad_slot = "6713161600";
/* Do not change anything after this line */
if ( adWidth >= 728 )
google_ad_size = ["728", "90"]; /* Leaderboard 728x90 */
else if ( adWidth >= 468 )
google_ad_size = ["468", "60"]; /* Banner (468 x 60) */
else if ( adWidth >= 336 )
google_ad_size = ["336", "600"]; /* Large Rectangle (336 x 280) */
else if ( adWidth >= 300 )
google_ad_size = ["300", "600"]; /* Medium Rectangle (300 x 250) */
else if ( adWidth >= 250 )
google_ad_size = ["250", "250"]; /* Square (250 x 250) */
else if ( adWidth >= 200 )
google_ad_size = ["200", "200"]; /* Small Square (200 x 200) */
else if ( adWidth >= 180 )
google_ad_size = ["180", "150"]; /* Small Rectangle (180 x 150) */
else
google_ad_size = ["125", "250"]; /* Button (125 x 125) */
document.write (
``
);
(adsbygoogle = window.adsbygoogle || []).push({});
Educational Qualification:
Candidates need to be Graduate Degree in Engineering (Mech)
Important Dates:
Last Date – 03-10-2019
How to Apply:
Eligible candidates can apply at UPSC website.
Go to upsconline.nic.in.
Search for the required post and click on the link.
Fill the details in the application form and upload the photo, signature, and documents.
Pay the application fee and submit the online application.